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10x^2+90x+180=0
a = 10; b = 90; c = +180;
Δ = b2-4ac
Δ = 902-4·10·180
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(90)-30}{2*10}=\frac{-120}{20} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(90)+30}{2*10}=\frac{-60}{20} =-3 $
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